What is the first derivative of y=8x+7 ?

The first derivative of y=8x+7 is 8

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derivative of y=8x+7

derivative of

y = 8 x + 7

8

Solution steps

\frac{d}{d x} (8 x + 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 x) + \frac{d}{d x} (7)

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (7) = 0

= 8 + 0

Simplify

= 8

t \to 1 lim (t + 8)

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