What is the solution for (dy}{dx}=-\frac{sin(x))/y ?

The solution for (dy}{dx}=-\frac{sin(x))/y is y=sqrt(2cos(x)+c_{1)},y=-sqrt(2cos(x)+c_{1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy}{dx}=-\frac{sin(x))/y

\frac{d y}{d x} = - \frac{sin ( x )}{y}

y = 2 cos (x) + c_{1}, y = - 2 cos (x) + c_{1}

Solution steps

\frac{d y}{d x} = - \frac{sin ( x )}{y}

Solve separable ODE:

y = 2 cos (x) + c_{1}, y = - 2 cos (x) + c_{1}

y = 2 cos (x) + c_{1}, y = - 2 cos (x) + c_{1}

\int cos (r^{2}) d r

x y^{^{'}} = (1 - x) y + x^{2} + x^{3}

y^{^{''}} + 4 y^{^{'}} = cos^{2} (x)

\int - \frac{1}{10 - x} d x

\int cos^{3} (x) (sin (x)) d x

What is the solution for (dy}{dx}=-\frac{sin(x))/y ?
The solution for (dy}{dx}=-\frac{sin(x))/y is y=sqrt(2cos(x)+c_{1)},y=-sqrt(2cos(x)+c_{1)}