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人気のある微分積分 >

derivative y=5e^{5t+1}

解

導関数

y = 5 e^{5 t + 1}

解

25 e^{5 t + 1}

解答ステップ

\frac{d}{d t} (5 e^{5 t + 1})

定数を除去:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d t} (e^{5 t + 1})

連鎖法則を適用:

e^{5 t + 1} \frac{d}{d t} (5 t + 1)

= e^{5 t + 1} \frac{d}{d t} (5 t + 1)

\frac{d}{d t} (5 t + 1) = 5

= 5 e^{5 t + 1} \cdot 5

簡素化

= 25 e^{5 t + 1}

グラフ

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