What is the tangent of y=3x^2+3,(2,15) ?

The tangent of y=3x^2+3,(2,15) is y=12x-9

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tangent of y=3x^2+3,(2,15)

tangent of

y = 3 x^{2} + 3, (2, 15)

y = 12 x - 9

Solution steps

Find the slope of

y = 3 x^{2} + 3 : \frac{d y}{d x} = 6 x

Compute the slope of

y = 3 x^{2} + 3

(2, 15) : m = 12

Find the line with slope m=

12

and passing through

(2, 15) : y = 12 x - 9

y = 12 x - 9

\frac{\partial}{\partial x} (e^{k x - m t})

\frac{d}{d x} (x^{2} arctan (8 x))

\int 9 cos (t) d t

\frac{ln ( x )}{x}

\int \frac{x ^{2} - 3 x - 10}{x + 2} d x

What is the tangent of y=3x^2+3,(2,15) ?
The tangent of y=3x^2+3,(2,15) is y=12x-9