What is the solution for y^'= x/(6y) ?

The solution for y^'= x/(6y) is y=sqrt((x^2)/6+c_{1)},y=-sqrt((x^2)/6+c_{1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'= x/(6y)

y^{^{'}} = \frac{x}{6 y}

y = \frac{x ^{2}}{6} + c_{1}, y = - \frac{x ^{2}}{6} + c_{1}

Solution steps

y^{'} (x) = \frac{x}{6 y}

Solve separable ODE:

y = \frac{x ^{2}}{6} + c_{1}, y = - \frac{x ^{2}}{6} + c_{1}

y = \frac{x ^{2}}{6} + c_{1}, y = - \frac{x ^{2}}{6} + c_{1}

\frac{d y}{d t} = 0.12 - \frac{6 y}{50 - 2 t}

\int x sin (x + 1) d x

\int 3 tan^{2} (x) d x

\frac{d y}{d x} = \frac{( y ^{2} - y )}{x}

\frac{\partial}{\partial x} (x e^{x} + 2 e^{x} y)

What is the solution for y^'= x/(6y) ?
The solution for y^'= x/(6y) is y=sqrt((x^2)/6+c_{1)},y=-sqrt((x^2)/6+c_{1)}