(\partial)/(\partial x)(sqrt(16-x^2-y^2))

解答

\frac{\partial}{\partial x} (16 - x^{2} - y^{2})

- \frac{x}{16 - x ^{2} - y ^{2}}

求解步骤

\frac{\partial}{\partial x} (16 - x^{2} - y^{2})

将

y

视为常数

使用连锁律:

\frac{1}{2 16 - x ^{2} - y ^{2}} \frac{\partial}{\partial x} (16 - x^{2} - y^{2})

= \frac{1}{2 16 - x ^{2} - y ^{2}} \frac{\partial}{\partial x} (16 - x^{2} - y^{2})

\frac{\partial}{\partial x} (16 - x^{2} - y^{2}) = - 2 x

= \frac{1}{2 16 - x ^{2} - y ^{2}} (- 2 x)

化简

\frac{1}{2 16 - x ^{2} - y ^{2}} (- 2 x) : - \frac{x}{16 - x ^{2} - y ^{2}}

= - \frac{x}{16 - x ^{2} - y ^{2}}

a re a y = e^{- 2 x} + 1, y = 0, x = 0, x = 3

\frac{\partial}{\partial t} (3 e^{s i n (x + 4 c t)})

f (x) = x^{6 x}

y^{^{'}} = \frac{( 4 x ^{3} + y ^{3} )}{x y ^{2}}

n = 0 \sum \infty \frac{1}{2 n !}