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Popular >

integral from-1 to 1 of x+1

Solution

\int_{- 1}^{1} x + 1 d x

Solution

2

Solution steps

\int_{- 1}^{1} x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} x d x + \int_{- 1}^{1} 1 d x

\int_{- 1}^{1} x d x = 0

\int_{- 1}^{1} 1 d x = 2

= 0 + 2

Simplify

= 2

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\int_{0}^{\frac{1}{2}} \frac{1}{1 + 4 x ^{2}} d x

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Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of x+1 ?
The integral from-1 to 1 of x+1 is 2