en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'+y=-x

Solution

y^{^{'}} + y = - x

Solution

y = - x + 1 + \frac{c _{1}}{e ^{x}}

Solution steps

y^{'} (x) + y = - x

Solve linear ODE:

y = - x + 1 + \frac{c _{1}}{e ^{x}}

y = - x + 1 + \frac{c _{1}}{e ^{x}}

Popular Examples

limit as x approaches 0 of (((6+x)^{-1}-6^{-1}))/x

x \to 0 lim \frac{( ( 6 + x ) ^{- 1} - 6 ^{- 1} )}{x}

derivative of f(x)=(x^2-6x+12)/(x-4)derivative of

f (x) = \frac{x ^{2} - 6 x + 12}{x - 4}

slope of x^2-3x slope

x^{2} - 3 x

integral from 0 to 3 of 1/(x^4)

\int_{0}^{3} \frac{1}{x ^{4}} d x

integral of 18cot^4(x)

\int 18 cot^{4} (x) d x

Frequently Asked Questions (FAQ)

What is the solution for y^'+y=-x ?
The solution for y^'+y=-x is y=-x+1+(c_{1})/(e^x)