derivative arcsin(4x)

解答

导数

arcsin (4 x)

\frac{4}{1 - 16 x ^{2}}

求解步骤

\frac{d}{d x} (arcsin (4 x))

使用连锁律:

\frac{1}{1 - ( 4 x ) ^{2}} \frac{d}{d x} (4 x)

= \frac{1}{1 - ( 4 x ) ^{2}} \frac{d}{d x} (4 x)

\frac{d}{d x} (4 x) = 4

= \frac{1}{1 - ( 4 x ) ^{2}} \cdot 4

化简

\frac{1}{1 - ( 4 x ) ^{2}} \cdot 4 : \frac{4}{1 - 16 x ^{2}}

= \frac{4}{1 - 16 x ^{2}}

\int \frac{x ^{3}}{y ^{2}} d x

t a y l or \frac{1}{( x + 1 ) ^{2}} 1

\int x^{2} 9 + x^{2} d x

in v erse l a pl a ce \frac{1}{2002 s ^{2} + 9}

y^{^{'}} = \frac{x ^{3} y ^{3} + 4 x ^{3}}{y ^{2}}