What is the derivative of arcsin(4x) ?

The derivative of arcsin(4x) is 4/(sqrt(1-16x^2))

What is the first derivative of arcsin(4x) ?

The first derivative of arcsin(4x) is 4/(sqrt(1-16x^2))

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derivative of

arcsin (4 x)

\frac{4}{1 - 16 x ^{2}}

Solution steps

\frac{d}{d x} (arcsin (4 x))

Apply the chain rule:

\frac{1}{1 - ( 4 x ) ^{2}} \frac{d}{d x} (4 x)

= \frac{1}{1 - ( 4 x ) ^{2}} \frac{d}{d x} (4 x)

\frac{d}{d x} (4 x) = 4

= \frac{1}{1 - ( 4 x ) ^{2}} \cdot 4

Simplify

\frac{1}{1 - ( 4 x ) ^{2}} \cdot 4 : \frac{4}{1 - 16 x ^{2}}

= \frac{4}{1 - 16 x ^{2}}

\int \frac{x ^{3}}{y ^{2}} d x

\frac{1}{( x + 1 ) ^{2}} 1

\int x^{2} 9 + x^{2} d x

\frac{1}{2002 s ^{2} + 9}

y^{^{'}} = \frac{x ^{3} y ^{3} + 4 x ^{3}}{y ^{2}}

What is the derivative of arcsin(4x) ?
The derivative of arcsin(4x) is 4/(sqrt(1-16x^2))
What is the first derivative of arcsin(4x) ?
The first derivative of arcsin(4x) is 4/(sqrt(1-16x^2))