What is the integral from 0 to infinity of e^{-14x} ?

The integral from 0 to infinity of e^{-14x} is 1/14

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to infinity of e^{-14x}

\int_{0}^{\infty} e^{- 14 x} d x

\frac{1}{14}

Decimal Notation

0.07142 \dots

Solution steps

\int_{0}^{\infty} e^{- 14 x} d x

Compute the indefinite integral:

\int e^{- 14 x} d x = - \frac{1}{14} e^{- 14 x} + C

Compute the boundaries:

\int_{0}^{\infty} e^{- 14 x} d x = 0 - (- \frac{1}{14})

= 0 - (- \frac{1}{14})

Simplify

= \frac{1}{14}

\frac{d ^{3}}{d x ^{3}} (\frac{1 - 5 x}{1 + 5 x})

x \to - 3 lim (14)

f (x) = x^{2} + 8, (2, 12)

\int 3 x^{\frac{2}{3}} d x

- \frac{3}{x ^{3}}

What is the integral from 0 to infinity of e^{-14x} ?
The integral from 0 to infinity of e^{-14x} is 1/14