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Popular >

y^'=9y^2sin(x)

Solution

y^{^{'}} = 9 y^{2} sin (x)

Solution

y = - \frac{1}{- 9 cos ( x ) + c _{1}}

Solution steps

y^{'} (x) = 9 y^{2} sin (x)

Solve separable ODE:

y = - \frac{1}{- 9 cos ( x ) + c _{1}}

y = - \frac{1}{- 9 cos ( x ) + c _{1}}

Popular Examples

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f (x) = 3 x^{3} + 5 x^{2} + 5 x, at x = - 1

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\frac{d}{d x} (2^{x} - 2 x)

area y=2x^2,y=2x+6,-2,2 area

y = 2 x^{2}, y = 2 x + 6, - 2, 2

y(dy)/(dx)+8x^3=4x

y \frac{d y}{d x} + 8 x^{3} = 4 x

integral of tan(6x)

\int tan (6 x) d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=9y^2sin(x) ?
The solution for y^'=9y^2sin(x) is y=-1/(-9cos(x)+c_{1)}