What is the solution for y(dy)/(dx)+8x^3=4x ?

The solution for y(dy)/(dx)+8x^3=4x is y=sqrt(4x^2-4x^4+c_{1)},y=-sqrt(4x^2-4x^4+c_{1)}

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y(dy)/(dx)+8x^3=4x

y \frac{d y}{d x} + 8 x^{3} = 4 x

y = 4 x^{2} - 4 x^{4} + c_{1}, y = - 4 x^{2} - 4 x^{4} + c_{1}

Solution steps

y \frac{d y}{d x} + 8 x^{3} = 4 x

Solve separable ODE:

y = 4 x^{2} - 4 x^{4} + c_{1}, y = - 4 x^{2} - 4 x^{4} + c_{1}

y = 4 x^{2} - 4 x^{4} + c_{1}, y = - 4 x^{2} - 4 x^{4} + c_{1}

\int tan (6 x) d x

\frac{d}{d x} (2 e^{x - 5})

y = - 9 x^{2}

n = 1 \sum \infty \frac{( - 1 ) ^{n - 1} n ^{2}}{1 0 ^{n}}

\frac{d}{d x} (\frac{x ^{2} - 3 x}{2 x + 1})

What is the solution for y(dy)/(dx)+8x^3=4x ?
The solution for y(dy)/(dx)+8x^3=4x is y=sqrt(4x^2-4x^4+c_{1)},y=-sqrt(4x^2-4x^4+c_{1)}