What is the sum from n=1 to infinity of 1/(n^{0.3)} ?

The sum from n=1 to infinity of 1/(n^{0.3)} is diverges

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sum from n=1 to infinity of 1/(n^{0.3)}

n = 1 \sum \infty \frac{1}{n ^{0.3}}

diverges

Solution steps

n = 1 \sum \infty \frac{1}{n ^{0.3}}

Apply p-Series Test:

diverges

= diverges

\int - e^{- y} d y

f (x) = x^{2} \cdot sin (x)

\frac{d}{d x} (\frac{( x ^{3} - 1 )}{( x ^{3} + 1 )})

y = 0.03 x^{2} + 1

\int_{2}^{3} \frac{1}{4 - 3 x} d x

What is the sum from n=1 to infinity of 1/(n^{0.3)} ?
The sum from n=1 to infinity of 1/(n^{0.3)} is diverges