What is the derivative of y=(5t-1)(6t-3)^{-1} ?

The derivative of y=(5t-1)(6t-3)^{-1} is -1/((2t-1)^2)

What is the first derivative of y=(5t-1)(6t-3)^{-1} ?

The first derivative of y=(5t-1)(6t-3)^{-1} is -1/((2t-1)^2)

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derivative of

y = (5 t - 1) (6 t - 3)^{- 1}

- \frac{1}{( 2 t - 1 ) ^{2}}

Solution steps

\frac{d}{d t} ((5 t - 1) (6 t - 3)^{- 1})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 5 t - 1, g = (6 t - 3)^{- 1}

= \frac{d}{d t} (5 t - 1) (6 t - 3)^{- 1} + \frac{d}{d t} ((6 t - 3)^{- 1}) (5 t - 1)

\frac{d}{d t} (5 t - 1) = 5

\frac{d}{d t} ((6 t - 3)^{- 1}) = - \frac{2}{3 ( 2 t - 1 ) ^{2}}

= 5 (6 t - 3)^{- 1} + (- \frac{2}{3 ( 2 t - 1 ) ^{2}}) (5 t - 1)

Simplify

5 (6 t - 3)^{- 1} + (- \frac{2}{3 ( 2 t - 1 ) ^{2}}) (5 t - 1) : - \frac{1}{( 2 t - 1 ) ^{2}}

= - \frac{1}{( 2 t - 1 ) ^{2}}

f (x) = x + 4 e^{x}

\frac{d}{d t} (a cos (wt))

y = 2 x^{2} + 8 x + 10

\frac{d}{d x} ((4 x^{2} + 5) (5 x - 3))

x \to 90 lim (cos (x))

What is the derivative of y=(5t-1)(6t-3)^{-1} ?
The derivative of y=(5t-1)(6t-3)^{-1} is -1/((2t-1)^2)
What is the first derivative of y=(5t-1)(6t-3)^{-1} ?
The first derivative of y=(5t-1)(6t-3)^{-1} is -1/((2t-1)^2)