What is the derivative of y=2x^2+8x+10 ?

The derivative of y=2x^2+8x+10 is 4x+8

What is the first derivative of y=2x^2+8x+10 ?

The first derivative of y=2x^2+8x+10 is 4x+8

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derivative of

y = 2 x^{2} + 8 x + 10

4 x + 8

Solution steps

\frac{d}{d x} (2 x^{2} + 8 x + 10)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (8 x) + \frac{d}{d x} (10)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (10) = 0

= 4 x + 8 + 0

Simplify

= 4 x + 8

\frac{d}{d x} ((4 x^{2} + 5) (5 x - 3))

x \to 90 lim (cos (x))

f (4) = 4 x^{\frac{5}{4}} + 8 x^{\frac{3}{2}} + 8 x

\frac{d ^{2}}{d x ^{2}} (sec (θ))

What is the derivative of y=2x^2+8x+10 ?
The derivative of y=2x^2+8x+10 is 4x+8
What is the first derivative of y=2x^2+8x+10 ?
The first derivative of y=2x^2+8x+10 is 4x+8