derivative f(4)=4x^{5/4}+8x^{3/2}+8x

Lösung

ableitung von

f (4) = 4 x^{\frac{5}{4}} + 8 x^{\frac{3}{2}} + 8 x

5 x^{\frac{1}{4}} + 12 x^{\frac{1}{2}} + 8

Schritte zur Lösung

\frac{d}{d x} (4 x^{\frac{5}{4}} + 8 x^{\frac{3}{2}} + 8 x)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{\frac{5}{4}}) + \frac{d}{d x} (8 x^{\frac{3}{2}}) + \frac{d}{d x} (8 x)

\frac{d}{d x} (4 x^{\frac{5}{4}}) = 5 x^{\frac{1}{4}}

\frac{d}{d x} (8 x^{\frac{3}{2}}) = 12 x^{\frac{1}{2}}

\frac{d}{d x} (8 x) = 8

= 5 x^{\frac{1}{4}} + 12 x^{\frac{1}{2}} + 8

\frac{d ^{2}}{d x ^{2}} (sec (θ))

d er i v a t i v e - \frac{1}{x ^{3}}

\int_{- \infty}^{0} e^{- 3 x} d x

t a y l or x^{3} + 2 x + 1, 2

y^{^{''}} + 64 y = 0, y (0) = 1, y^{^{'}} (0) = 5