What is the derivative of f(4)=4x^{5/4}+8x^{3/2}+8x ?

The derivative of f(4)=4x^{5/4}+8x^{3/2}+8x is 5x^{1/4}+12x^{1/2}+8

What is the first derivative of f(4)=4x^{5/4}+8x^{3/2}+8x ?

The first derivative of f(4)=4x^{5/4}+8x^{3/2}+8x is 5x^{1/4}+12x^{1/2}+8

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derivative of

f (4) = 4 x^{\frac{5}{4}} + 8 x^{\frac{3}{2}} + 8 x

5 x^{\frac{1}{4}} + 12 x^{\frac{1}{2}} + 8

Solution steps

\frac{d}{d x} (4 x^{\frac{5}{4}} + 8 x^{\frac{3}{2}} + 8 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{\frac{5}{4}}) + \frac{d}{d x} (8 x^{\frac{3}{2}}) + \frac{d}{d x} (8 x)

\frac{d}{d x} (4 x^{\frac{5}{4}}) = 5 x^{\frac{1}{4}}

\frac{d}{d x} (8 x^{\frac{3}{2}}) = 12 x^{\frac{1}{2}}

\frac{d}{d x} (8 x) = 8

= 5 x^{\frac{1}{4}} + 12 x^{\frac{1}{2}} + 8

\frac{d ^{2}}{d x ^{2}} (sec (θ))

- \frac{1}{x ^{3}}

\int_{- \infty}^{0} e^{- 3 x} d x

x^{3} + 2 x + 1, 2

y^{^{''}} + 64 y = 0, y (0) = 1, y^{^{'}} (0) = 5

What is the derivative of f(4)=4x^{5/4}+8x^{3/2}+8x ?
The derivative of f(4)=4x^{5/4}+8x^{3/2}+8x is 5x^{1/4}+12x^{1/2}+8
What is the first derivative of f(4)=4x^{5/4}+8x^{3/2}+8x ?
The first derivative of f(4)=4x^{5/4}+8x^{3/2}+8x is 5x^{1/4}+12x^{1/2}+8