What is the solution for (d^2y)/(dx^2)+y=0 ?

The solution for (d^2y)/(dx^2)+y=0 is y=c_{1}cos(x)+c_{2}sin(x)

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(d^2y)/(dx^2)+y=0

\frac{d ^{2} y}{d x ^{2}} + y = 0

y = c_{1} cos (x) + c_{2} sin (x)

Solution steps

\frac{d ^{2} y}{d x ^{2}} + y = 0

Solve linear ODE:

y = c_{1} cos (x) + c_{2} sin (x)

y = c_{1} cos (x) + c_{2} sin (x)

y^{^{'}} - \frac{1}{x} y = x^{2} e^{x}

\frac{d}{d x} (\frac{cos ( 2 x )}{sin ( 3 x )})

\int_{0}^{16} t^{2} + 2 t + 1 d t

y^{^{'}} = \frac{( x ^{3} y ^{3} + 4 x ^{3} )}{y ^{2}}

\int_{\frac{1}{5}}^{3} 12 x ln (5 x) d x

What is the solution for (d^2y)/(dx^2)+y=0 ?
The solution for (d^2y)/(dx^2)+y=0 is y=c_{1}cos(x)+c_{2}sin(x)