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人気のある微分積分 >

derivative ax^2+bx+c

解

導関数

a x^{2} + b x + c

解

2 a x + b

解答ステップ

\frac{d}{d x} (a x^{2} + b x + c)

和/差の法則を適用:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (a x^{2}) + \frac{d}{d x} (b x) + \frac{d c}{d x}

\frac{d}{d x} (a x^{2}) = 2 a x

\frac{d}{d x} (b x) = b

\frac{d c}{d x} = 0

= 2 a x + b + 0

簡素化

= 2 a x + b

グラフ

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