What is (\partial)/(\partial y)(cos(x+4y)) ?

The answer to (\partial)/(\partial y)(cos(x+4y)) is -sin(x+4y)*4

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(\partial)/(\partial y)(cos(x+4y))

\frac{\partial}{\partial y} (cos (x + 4 y))

- sin (x + 4 y) \cdot 4

Solution steps

\frac{\partial}{\partial y} (cos (x + 4 y))

Treat

x

as a constant

Apply the chain rule:

- sin (x + 4 y) \frac{\partial}{\partial y} (x + 4 y)

= - sin (x + 4 y) \frac{\partial}{\partial y} (x + 4 y)

\frac{\partial}{\partial y} (x + 4 y) = 4

= - sin (x + 4 y) \cdot 4

\int e^{x} sin (x) d x

f (x) = \frac{1}{27} (9 x^{2} + 6)^{\frac{3}{2}}

\int e^{\frac{1}{2} x^{2}} d x

x \to 4 - lim (∣ x - 4 ∣)

y^{^{'}} = y + x^{2} e^{x} + 1 - \frac{1}{e}

What is (\partial)/(\partial y)(cos(x+4y)) ?
The answer to (\partial)/(\partial y)(cos(x+4y)) is -sin(x+4y)*4