What is the solution for y^{''}+4y=3sin(x) ?

The solution for y^{''}+4y=3sin(x) is y=c_{1}cos(2x)+c_{2}sin(2x)+sin(x)

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y^{''}+4y=3sin(x)

y^{^{''}} + 4 y = 3 sin (x)

y = c_{1} cos (2 x) + c_{2} sin (2 x) + sin (x)

Solution steps

y^{''} (x) + 4 y = 3 sin (x)

Solve linear ODE:

y = c_{1} cos (2 x) + c_{2} sin (2 x) + sin (x)

y = c_{1} cos (2 x) + c_{2} sin (2 x) + sin (x)

\frac{d V}{12 - 2 V} = d t, V (0) = 1

\frac{\partial}{\partial x} (\frac{x + 2 y}{3 x + 4 y})

\frac{d}{d θ} (cos (3 θ))

(1 + x + x^{2})^{99}

\int e^{5 x^{2} + 10 x + 10} (x + 1) d x

What is the solution for y^{''}+4y=3sin(x) ?
The solution for y^{''}+4y=3sin(x) is y=c_{1}cos(2x)+c_{2}sin(2x)+sin(x)