What is (\partial)/(\partial x)((2xy)/(x^2+y^2)) ?

The answer to (\partial)/(\partial x)((2xy)/(x^2+y^2)) is (2y(-x^2+y^2))/((x^2+y^2)^2)

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(\partial)/(\partial x)((2xy)/(x^2+y^2))

\frac{\partial}{\partial x} (\frac{2 x y}{x ^{2} + y ^{2}})

\frac{2 y ( - x ^{2} + y ^{2} )}{( x ^{2} + y ^{2} ) ^{2}}

Solution steps

\frac{\partial}{\partial x} (\frac{2 x y}{x ^{2} + y ^{2}})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 y \frac{\partial}{\partial x} (\frac{x}{x ^{2} + y ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 2 y \frac{\frac{\partial}{\partial x} ( x ) ( x ^{2} + y ^{2} ) - \frac{\partial}{\partial x} ( x ^{2} + y ^{2} ) x}{( x ^{2} + y ^{2} ) ^{2}}

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (x^{2} + y^{2}) = 2 x

= 2 y \frac{1 \cdot ( x ^{2} + y ^{2} ) - 2 xx}{( x ^{2} + y ^{2} ) ^{2}}

Simplify

2 y \frac{1 \cdot ( x ^{2} + y ^{2} ) - 2 xx}{( x ^{2} + y ^{2} ) ^{2}} : \frac{2 y ( - x ^{2} + y ^{2} )}{( x ^{2} + y ^{2} ) ^{2}}

= \frac{2 y ( - x ^{2} + y ^{2} )}{( x ^{2} + y ^{2} ) ^{2}}

\int \frac{3}{2} t + 1 d t

\frac{d}{d x} (\frac{5 x ^{2} tan ( x )}{sec ( x )})

\int_{0}^{1} (8 x^{2} - 5) e^{x} d x

\frac{\partial}{\partial y} (2 y t + x j)

\int \frac{x ^{2}}{16 + x ^{2}} d x

What is (\partial)/(\partial x)((2xy)/(x^2+y^2)) ?
The answer to (\partial)/(\partial x)((2xy)/(x^2+y^2)) is (2y(-x^2+y^2))/((x^2+y^2)^2)