What is the limit as x approaches 1 of (x^4-6x^2+8x-3)/(x^4-2x^3+2x-1) ?

The limit as x approaches 1 of (x^4-6x^2+8x-3)/(x^4-2x^3+2x-1) is 2

Popular >

limit as x approaches 1 of (x^4-6x^2+8x-3)/(x^4-2x^3+2x-1)

x \to 1 lim (\frac{x ^{4} - 6 x ^{2} + 8 x - 3}{x ^{4} - 2 x ^{3} + 2 x - 1})

2

Solution steps

x \to 1 lim (\frac{x ^{4} - 6 x ^{2} + 8 x - 3}{x ^{4} - 2 x ^{3} + 2 x - 1})

Simplify

\frac{x ^{4} - 6 x ^{2} + 8 x - 3}{x ^{4} - 2 x ^{3} + 2 x - 1} : \frac{x + 3}{x + 1}

= x \to 1 lim (\frac{x + 3}{x + 1})

Plug in the value

x = 1

= \frac{1 + 3}{1 + 1}

Simplify

= 2

\int_{0}^{2} 2 π (9 - x) (8 - x^{3}) d x

\int_{120}^{150} 0.1281 \cdot x \cdot e^{- \frac{x}{100}} d x

4 y + y^{^{''}} = 0

(\frac{1}{x ^{2}} - \frac{3}{x ^{4}}) (x + 9 x^{3})

\int \frac{2}{( 1 + x ^{2} ) ^{2}} d x

What is the limit as x approaches 1 of (x^4-6x^2+8x-3)/(x^4-2x^3+2x-1) ?
The limit as x approaches 1 of (x^4-6x^2+8x-3)/(x^4-2x^3+2x-1) is 2