What is (\partial)/(\partial x)(in(x+2y+3z)) ?

The answer to (\partial)/(\partial x)(in(x+2y+3z)) is in

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(\partial)/(\partial x)(in(x+2y+3z))

\frac{\partial}{\partial x} (in (x + 2 y + 3 z))

in

Solution steps

\frac{\partial}{\partial x} (in (x + 2 y + 3 z))

Simplify

in (x + 2 y + 3 z) : i (n x + 2 n y + 3 n z)

= \frac{\partial}{\partial x} (i (n x + 2 n y + 3 n z))

Treat

n, y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= i \frac{\partial}{\partial x} (n x + 2 n y + 3 n z)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= i (\frac{\partial}{\partial x} (n x) + \frac{\partial}{\partial x} (2 n y) + \frac{\partial}{\partial x} (3 n z))

\frac{\partial}{\partial x} (n x) = n

\frac{\partial}{\partial x} (2 n y) = 0

\frac{\partial}{\partial x} (3 n z) = 0

= i (n + 0 + 0)

Simplify

= in

x \to 1 lim (\frac{1}{1 - x})

\int \frac{( ln ( x ) ) ^{48}}{x} d x

ln (3 - 5 x)

\frac{d}{d x} (\frac{3 tan ( x )}{x})

f (x) = \frac{( a x + b )}{c x + d}

What is (\partial)/(\partial x)(in(x+2y+3z)) ?
The answer to (\partial)/(\partial x)(in(x+2y+3z)) is in