integral from 1 to 2 of x^2-4x+3

Lösung

\int_{1}^{2} x^{2} - 4 x + 3 d x

- \frac{2}{3}

Dezimale

- 0.66666 \dots

Schritte zur Lösung

\int_{1}^{2} x^{2} - 4 x + 3 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} x^{2} d x - \int_{1}^{2} 4 x d x + \int_{1}^{2} 3 d x

\int_{1}^{2} x^{2} d x = \frac{7}{3}

\int_{1}^{2} 4 x d x = 6

\int_{1}^{2} 3 d x = 3

= \frac{7}{3} - 6 + 3

Vereinfache

\frac{7}{3} - 6 + 3 : - \frac{2}{3}

= - \frac{2}{3}

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