What is the integral from-2 to-1 of (x^2-x-2) ?

The integral from-2 to-1 of (x^2-x-2) is 11/6

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integral from-2 to-1 of (x^2-x-2)

\int_{- 2}^{- 1} (x^{2} - x - 2) d x

\frac{11}{6}

Decimal Notation

1.83333 \dots

Solution steps

\int_{- 2}^{- 1} x^{2} - x - 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{- 1} x^{2} d x - \int_{- 2}^{- 1} x d x - \int_{- 2}^{- 1} 2 d x

\int_{- 2}^{- 1} x^{2} d x = \frac{7}{3}

\int_{- 2}^{- 1} x d x = - \frac{3}{2}

\int_{- 2}^{- 1} 2 d x = 2

= \frac{7}{3} - (- \frac{3}{2}) - 2

Simplify

\frac{7}{3} - (- \frac{3}{2}) - 2 : \frac{11}{6}

= \frac{11}{6}

f (x) = e^{x} ln (x)

x \to 0 lim (\frac{sin ( 4 x )}{6})

\frac{\partial}{\partial y} (x e^{y^{2}} + y ln (x))

\int \frac{6}{( x - 4 ) ( x + 2 )} d x

y^{^{''}} + 81 y = sec^{2} (9 x)

What is the integral from-2 to-1 of (x^2-x-2) ?
The integral from-2 to-1 of (x^2-x-2) is 11/6