What is (\partial)/(\partial x)((x^2+y^2-7)/(xy)) ?

The answer to (\partial)/(\partial x)((x^2+y^2-7)/(xy)) is (x^2-y^2+7)/(x^2y)

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(\partial)/(\partial x)((x^2+y^2-7)/(xy))

\frac{\partial}{\partial x} (\frac{x ^{2} + y ^{2} - 7}{x y})

\frac{x ^{2} - y ^{2} + 7}{x ^{2} y}

Solution steps

\frac{\partial}{\partial x} (\frac{x ^{2} + y ^{2} - 7}{x y})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{y} \frac{\partial}{\partial x} (\frac{x ^{2} + y ^{2} - 7}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{1}{y} \cdot \frac{\frac{\partial}{\partial x} ( x ^{2} + y ^{2} - 7 ) x - \frac{\partial}{\partial x} ( x ) ( x ^{2} + y ^{2} - 7 )}{x ^{2}}

\frac{\partial}{\partial x} (x^{2} + y^{2} - 7) = 2 x

\frac{\partial}{\partial x} (x) = 1

= \frac{1}{y} \cdot \frac{2 xx - 1 \cdot ( x ^{2} + y ^{2} - 7 )}{x ^{2}}

Simplify

\frac{1}{y} \cdot \frac{2 xx - 1 \cdot ( x ^{2} + y ^{2} - 7 )}{x ^{2}} : \frac{x ^{2} - y ^{2} + 7}{x ^{2} y}

= \frac{x ^{2} - y ^{2} + 7}{x ^{2} y}

\frac{d x}{d t} + 3 t^{3} x^{5} + \frac{x}{t} = 0

x^{2} + 8 x - 2

x^{2} d y + 2 x y d x = 0

\frac{d ^{2}}{d x ^{2}} (- cos (x) ln (sec (x) + tan (x)))

\int \frac{10}{x ^{5}} d x

What is (\partial)/(\partial x)((x^2+y^2-7)/(xy)) ?
The answer to (\partial)/(\partial x)((x^2+y^2-7)/(xy)) is (x^2-y^2+7)/(x^2y)