What is the integral of (ln(11x))^2 ?

The integral of (ln(11x))^2 is xln^2(11x)-2(xln(11x)-x)+C

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integral of (ln(11x))^2

\int (ln (11 x))^{2} d x

x ln^{2} (11 x) - 2 (x ln (11 x) - x) + C

Solution steps

\int (ln (11 x))^{2} d x

Apply Integration By Parts

: x ln^{2} (11 x) - \int 2 ln (11 x) d x

= x ln^{2} (11 x) - \int 2 ln (11 x) d x

\int 2 ln (11 x) d x = 2 (x ln (11 x) - x)

= x ln^{2} (11 x) - 2 (x ln (11 x) - x)

Add a constant to the solution

= x ln^{2} (11 x) - 2 (x ln (11 x) - x) + C

3 x + 7

- 2.25 cos (1.5 x)

\int_{0}^{33} (x - 1)^{- \frac{1}{5}} d x

y = (x^{2} + 4) (x^{3} - 4 x), (- 2, 0)

x \to - 2 lim (x^{2} - 3 x + 1)

What is the integral of (ln(11x))^2 ?
The integral of (ln(11x))^2 is xln^2(11x)-2(xln(11x)-x)+C