integral from 2 to-1 of (x^2-x-2)

Lösung

\int_{2}^{- 1} (x^{2} - x - 2) d x

\frac{9}{2}

Dezimale

4.5

Schritte zur Lösung

\int_{2}^{- 1} x^{2} - x - 2 d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{- 1}^{2} x^{2} - x - 2 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - (\int_{- 1}^{2} x^{2} d x - \int_{- 1}^{2} x d x - \int_{- 1}^{2} 2 d x)

\int_{- 1}^{2} x^{2} d x = 3

\int_{- 1}^{2} x d x = \frac{3}{2}

\int_{- 1}^{2} 2 d x = 6

= - (3 - \frac{3}{2} - 6)

Vereinfache

- (3 - \frac{3}{2} - 6) : \frac{9}{2}

= \frac{9}{2}

\int_{1}^{2} \frac{x}{( x ^{2} + 4 ) ^{3}} d x

\int_{- 1}^{1} cos (\frac{π}{3} x) d x

\int_{0}^{2} 4 t - 3 t^{2} d t

\int_{0}^{2 - x} 2 - x - y d y

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