integral from 0 to x of ((sin(t))/t-1)

Lösung

\int_{0}^{x} (\frac{sin ( t )}{t} - 1) d t

Si (x) - x

Schritte zur Lösung

\int_{0}^{x} \frac{sin ( t )}{t} - 1 d t

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{x} \frac{sin ( t )}{t} d t - \int_{0}^{x} 1 d t

\int_{0}^{x} \frac{sin ( t )}{t} d t = Si (x)

\int_{0}^{x} 1 d t = x

= Si (x) - x

\int_{0}^{1} (1 - 8 v^{3} + 16 v^{7}) d v

\int_{2}^{3} 12 - 4 x d x

\int_{3}^{4} (ln (x))^{2} d x

\int_{0}^{2} (x^{2} - 3 x + 5) d x

\int_{2}^{6} 3 x d x