integral from 1 to 2 of 4/(x^3)

Lösung

\int_{1}^{2} \frac{4}{x ^{3}} d x

\frac{3}{2}

Dezimale

1.5

Schritte zur Lösung

\int_{1}^{2} \frac{4}{x ^{3}} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int_{1}^{2} \frac{1}{x ^{3}} d x

Wende die Potenzregel an

= 4 [- \frac{1}{2 x ^{2}}]_{1}^{2}

Berechne die Grenzen:

\frac{3}{8}

= 4 \cdot \frac{3}{8}

Vereinfache

= \frac{3}{2}

\int_{1}^{10} x \frac{2}{81} (x - 1) d x

\int_{3}^{\infty} e^{- s t} d t

\int_{0}^{9} (81 - x^{2}) d x

\int_{0}^{5} e^{x^{2}} d x

\int_{- 4}^{3} - x^{2} - 3 x d x