integral from 0 to 4 of |3x-8|

Lösung

\int_{0}^{4} ∣ 3 x - 8 ∣ d x

\frac{40}{3}

Dezimale

13.33333 \dots

Schritte zur Lösung

\int_{0}^{4} ∣ 3 x - 8 ∣ d x

Entferne die Extremwerte

= \int_{0}^{\frac{8}{3}} - 3 x + 8 d x + \int_{\frac{8}{3}}^{4} 3 x - 8 d x

\int_{0}^{\frac{8}{3}} - 3 x + 8 d x = \frac{32}{3}

\int_{\frac{8}{3}}^{4} 3 x - 8 d x = \frac{8}{3}

= \frac{32}{3} + \frac{8}{3}

Vereinfache

\frac{32}{3} + \frac{8}{3} : \frac{40}{3}

= \frac{40}{3}

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