integral from 1 to 5 of 2/(x^2)+x

Lösung

\int_{1}^{5} \frac{2}{x ^{2}} + x d x

\frac{68}{5}

Dezimale

13.6

Schritte zur Lösung

\int_{1}^{5} \frac{2}{x ^{2}} + x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{5} \frac{2}{x ^{2}} d x + \int_{1}^{5} x d x

\int_{1}^{5} \frac{2}{x ^{2}} d x = \frac{8}{5}

\int_{1}^{5} x d x = 12

= \frac{8}{5} + 12

Vereinfache

\frac{8}{5} + 12 : \frac{68}{5}

= \frac{68}{5}

\int_{1}^{3} \frac{x}{( x ^{2} + 9 ) ^{3}} d x

\int_{0}^{3} x^{2} + 3 d x

\int_{0}^{2 π} - 54 sin^{2} (t) d t

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