integral from 0 to b of 6e^x

Lösung

\int_{0}^{b} 6 e^{x} d x

6 (e^{b} - 1)

Schritte zur Lösung

\int_{0}^{b} 6 e^{x} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int_{0}^{b} e^{x} d x

Nutze das gemeinsame Integral :

\int e^{x} d x = e^{x}

= 6 [e^{x}]_{0}^{b}

Berechne die Grenzen:

e^{b} - 1

= 6 (e^{b} - 1)

\int_{0}^{1} (- 5 x^{3} - 4 x^{2} + 9 x) d x

\int_{- 2}^{2} (x^{2} + 2 x) d x

\int_{1}^{3} \frac{1}{x - 1} d x

\int_{- 5}^{c o s (x)} \frac{1}{t ^{2} - 1} d t

\int_{- 2}^{2} (∣ x ∣ + x) e^{∣ x ∣} d x