integral from 1 to 2 of (2x+4)

Lösung

\int_{1}^{2} (2 x + 4) d x

7

Schritte zur Lösung

\int_{1}^{2} 2 x + 4 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 2 x d x + \int_{1}^{2} 4 d x

\int_{1}^{2} 2 x d x = 3

\int_{1}^{2} 4 d x = 4

= 3 + 4

Vereinfache

= 7

\int_{0}^{a} x d x

\int_{0}^{1} (e^{2 x}) d x

\int_{0}^{1} (3 x^{e} + 4 e^{x}) d x

\int_{0}^{16} t d t

\int_{1}^{3} sin (z^{2}) d z