integral from k to x of 1/(sqrt(t))

Lösung

\int_{k}^{x} \frac{1}{t} d t

2 x - 2 k

Schritte zur Lösung

\int_{k}^{x} \frac{1}{t} d t

Wende die Potenzregel an

= [2 t^{\frac{1}{2}}]_{k}^{x}

Wende Radikal Regel an:

a^{\frac{1}{n}} = n a

= [2 t]_{k}^{x}

Berechne die Grenzen:

2 x - 2 k

= 2 x - 2 k

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