What is the tangent of y=2x^3-2x,(-1,0) ?

The tangent of y=2x^3-2x,(-1,0) is y=4x+4

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tangent of y=2x^3-2x,(-1,0)

tangent of

y = 2 x^{3} - 2 x, (- 1, 0)

y = 4 x + 4

Solution steps

Find the slope of

y = 2 x^{3} - 2 x : \frac{d y}{d x} = 6 x^{2} - 2

Compute the slope of

y = 2 x^{3} - 2 x

(- 1, 0) : m = 4

Find the line with slope m=

4

and passing through

(- 1, 0) : y = 4 x + 4

y = 4 x + 4

\frac{d}{d x} (e \frac{- x}{2})

\frac{( e ^{x} )}{x}

x \to 0 lim (2 x)

\int e^{2 x} ln (x) d x

\int (\frac{4}{x} + sec^{2} (x)) d x

What is the tangent of y=2x^3-2x,(-1,0) ?
The tangent of y=2x^3-2x,(-1,0) is y=4x+4