What is (\partial)/(\partial r)(r^2+s^2) ?

The answer to (\partial)/(\partial r)(r^2+s^2) is 2r

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial r)(r^2+s^2)

\frac{\partial}{\partial r} (r^{2} + s^{2})

2 r

Solution steps

\frac{\partial}{\partial r} (r^{2} + s^{2})

Treat

s

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial r} (r^{2}) + \frac{\partial}{\partial r} (s^{2})

\frac{\partial}{\partial r} (r^{2}) = 2 r

\frac{\partial}{\partial r} (s^{2}) = 0

= 2 r + 0

Simplify

= 2 r

x \to 3 - lim (\frac{5 x}{x ^{2} - 9})

\int_{0}^{5} \frac{1}{25 - x ^{2}} d x

x \to - 1 - lim (\frac{9}{x ^{3} - 1})

\int \frac{3}{16 - x ^{2}} d x

f (x) = 4 t

What is (\partial)/(\partial r)(r^2+s^2) ?
The answer to (\partial)/(\partial r)(r^2+s^2) is 2r