What is the limit as x approaches-1-of 9/(x^3-1) ?

The limit as x approaches-1-of 9/(x^3-1) is -9/2

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limit as x approaches-1-of 9/(x^3-1)

x \to - 1 - lim (\frac{9}{x ^{3} - 1})

- \frac{9}{2}

Decimal Notation

- 4.5

Solution steps

x \to - 1 - lim (\frac{9}{x ^{3} - 1})

Plug in the value

x = - 1

= \frac{9}{( - 1 ) ^{3} - 1}

Simplify

\frac{9}{( - 1 ) ^{3} - 1} : - \frac{9}{2}

= - \frac{9}{2}

\int \frac{3}{16 - x ^{2}} d x

f (x) = 4 t

x (x - 4)

n = 1 \sum \infty \frac{( - 1 ) ^{n} ( 2 ) ^{n - 1}}{( 2 ) ^{n + 1} ( n ) ^{\frac{1}{3}}}

\frac{2 x - 6}{x ^{2} + 9}

What is the limit as x approaches-1-of 9/(x^3-1) ?
The limit as x approaches-1-of 9/(x^3-1) is -9/2