What is the tangent of f(x)=2sin(x),\at x= pi/3 ?

The tangent of f(x)=2sin(x),\at x= pi/3 is y=x+sqrt(3)-pi/3

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tangent of f(x)=2sin(x),\at x= pi/3

tangent of

f (x) = 2 sin (x), at x = \frac{π}{3}

y = x + 3 - \frac{π}{3}

Solution steps

Find the tangent point:

(\frac{π}{3}, 3)

Find the slope of

f (x) = 2 sin (x) : \frac{df ( x )}{d x} = 2 cos (x)

Compute the slope of

f (x) = 2 sin (x)

x = \frac{π}{3} : m = 1

Find the line with slope m=

1

and passing through

(\frac{π}{3}, 3) : y = x + 3 - \frac{π}{3}

y = x + 3 - \frac{π}{3}

\int x^{2} 6 x + 5 d x

f (x) = 3 a^{3 x}

9 x^{2} + y = 9, x^{4} - y = 1

\int \frac{3}{y} d y

x \to 1 lim (\frac{- 3 x - 1}{x - 1})

What is the tangent of f(x)=2sin(x),\at x= pi/3 ?
The tangent of f(x)=2sin(x),\at x= pi/3 is y=x+sqrt(3)-pi/3