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Popular >

area 2sin(3θ),1

Solution

area

2 sin (3 θ), 1

Solution

\frac{2}{3} - \frac{2 π}{9}

+1

Decimal Notation

0.45656 \dots

Solution steps

Apply the area formula:

\int_{\frac{π}{18}}^{\frac{5 π}{18}} ∣ 2 sin (3 θ) - 1 ∣ d θ

Solve

\int_{\frac{π}{18}}^{\frac{5 π}{18}} ∣ 2 sin (3 θ) - 1 ∣ d θ : \frac{2}{3} - \frac{2 π}{9}

The area is:

= \frac{2}{3} - \frac{2 π}{9}

Popular Examples

derivative of 4e^{2x}x+4e^{2x}

\frac{d}{d x} (4 e^{2 x} x + 4 e^{2 x})

integral of (2x+3x^2)

\int (2 x + 3 x^{2}) d x

tangent of y=x^3-3x+1,(2,3)tangent of

y = x^{3} - 3 x + 1, (2, 3)

integral of (int)^2

\int (in t)^{2} d t

derivative of y=-18 derivative of

y = - 18

Frequently Asked Questions (FAQ)

What is area 2sin(3θ),1 ?
The answer to area 2sin(3θ),1 is 2/(sqrt(3))-(2pi)/9