What is the integral from 0 to 1 of ln(6x) ?

The integral from 0 to 1 of ln(6x) is ln(6)-1

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integral from 0 to 1 of ln(6x)

\int_{0}^{1} ln (6 x) d x

ln (6) - 1

Decimal Notation

0.79175 \dots

Solution steps

\int_{0}^{1} ln (6 x) d x

Apply Integration By Parts

: [x ln (6 x) - \int 1 d x]_{0}^{1}

= [x ln (6 x) - \int 1 d x]_{0}^{1}

\int 1 d x = x

= [x ln (6 x) - x]_{0}^{1}

Compute the boundaries:

ln (6) - 1

= ln (6) - 1

\int_{0}^{4} \frac{x ^{2}}{x ^{3} + 7} d x

f (x) = \frac{( e ^{x} )}{( 1 - e ^{x} )}

\int x^{2} (ln (x)) d x

\int (\frac{d}{1} (y))^{2} d x

\frac{( 4 s - 5 )}{s ^{2} - 6 s + 13}

What is the integral from 0 to 1 of ln(6x) ?
The integral from 0 to 1 of ln(6x) is ln(6)-1