What is the integral of (1 (y))^2 ?

The integral of (1 (y))^2 is d^2y^2x+C

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integral of (1 (y))^2

\int (\frac{d}{1} (y))^{2} d x

d^{2} y^{2} x + C

Solution steps

\int (\frac{d}{1} y)^{2} d x

Integral of a constant:

\int a d x = a x

= (\frac{d}{1} y)^{2} x

Simplify

(\frac{d}{1} y)^{2} x : d^{2} y^{2} x

= d^{2} y^{2} x

Add a constant to the solution

= d^{2} y^{2} x + C

\frac{( 4 s - 5 )}{s ^{2} - 6 s + 13}

n = 1 \sum \infty (\frac{1}{3})^{n}

4 x^{2}, \frac{x}{4}

y = x^{2} + 4, y = - x^{2} - 1, x = - 2, x = 3

30 ln (2 x + 1)