What is area y=x^2+4,y=-x^2-1,x=-2,x=3 ?

The answer to area y=x^2+4,y=-x^2-1,x=-2,x=3 is 145/3

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area y=x^2+4,y=-x^2-1,x=-2,x=3

area

y = x^{2} + 4, y = - x^{2} - 1, x = - 2, x = 3

\frac{145}{3}

Decimal Notation

48.33333 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{3} x^{2} + 4 - (- x^{2} - 1) d x

Solve

\int_{- 2}^{3} x^{2} + 4 - (- x^{2} - 1) d x : \frac{145}{3}

The area is:

= \frac{145}{3}

30 ln (2 x + 1)

x \to - 3 - lim (ln (x^{2} - 9))

\frac{d}{d x} (- \frac{6}{( 1 - x ) ^{2}})

- (\frac{64}{( 1 + 4 x ) ^{3}})

\int u^{2} + 1 d u

What is area y=x^2+4,y=-x^2-1,x=-2,x=3 ?
The answer to area y=x^2+4,y=-x^2-1,x=-2,x=3 is 145/3