What is the solution for y^'+y-2sin(x)=0 ?

The solution for y^'+y-2sin(x)=0 is y=-cos(x)+sin(x)+(c_{1})/(e^x)

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y^'+y-2sin(x)=0

y^{^{'}} + y - 2 sin (x) = 0

y = - cos (x) + sin (x) + \frac{c _{1}}{e ^{x}}

Solution steps

y^{'} (x) + y - 2 sin (x) = 0

Solve linear ODE:

y = - cos (x) + sin (x) + \frac{c _{1}}{e ^{x}}

y = - cos (x) + sin (x) + \frac{c _{1}}{e ^{x}}

\int_{- \infty}^{0} \frac{1}{7 - 2 x} d x

13 x^{3} (x^{2} - 5)

\frac{d}{d x} (arctan (\frac{0.9}{x}))

\frac{42}{x}

x \to - 2 lim (3 x + 8)

What is the solution for y^'+y-2sin(x)=0 ?
The solution for y^'+y-2sin(x)=0 is y=-cos(x)+sin(x)+(c_{1})/(e^x)