What is the integral from-infinity to 0 of 1/(7-2x) ?

The integral from-infinity to 0 of 1/(7-2x) is diverges

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integral from-infinity to 0 of 1/(7-2x)

\int_{- \infty}^{0} \frac{1}{7 - 2 x} d x

diverges

Solution steps

\int_{- \infty}^{0} \frac{1}{7 - 2 x} d x

Compute the indefinite integral:

\int \frac{1}{7 - 2 x} d x = - \frac{1}{2} ln ∣ 7 - 2 x ∣ + C

Compute the boundaries:

\int_{- \infty}^{0} \frac{1}{7 - 2 x} d x =

diverges

= diverges

13 x^{3} (x^{2} - 5)

\frac{d}{d x} (arctan (\frac{0.9}{x}))

\frac{42}{x}

x \to - 2 lim (3 x + 8)

y = e^{- x^{9}}

What is the integral from-infinity to 0 of 1/(7-2x) ?
The integral from-infinity to 0 of 1/(7-2x) is diverges