(dy)/(dx)=(3x+2y+1)/(3x+2y-1)

Lösung

\frac{d y}{d x} = \frac{3 x + 2 y + 1}{3 x + 2 y - 1}

y = \frac{- 2 W ( - \frac{1}{4 e ^{\frac{25 x + c _{1}}{4}}} ) + 3}{5} - \frac{3 x}{2} - \frac{1}{2}

Schritte zur Lösung

\frac{d y}{d x} = \frac{3 x + 2 y + 1}{3 x + 2 y - 1}

Solve using substitution:

y = \frac{- 2 W ( - \frac{1}{4 e ^{\frac{25 x + c _{1}}{4}}} ) + 3}{5} - \frac{3 x}{2} - \frac{1}{2}

y = \frac{- 2 W ( - \frac{1}{4 e ^{\frac{25 x + c _{1}}{4}}} ) + 3}{5} - \frac{3 x}{2} - \frac{1}{2}

d er i v a t i v e f (x) = (4 x^{2} - 8 x + 8) e^{x}

\frac{\partial}{\partial y} (x e^{2 y} sin (7 z))

\int_{- 8}^{64} \frac{1}{3 x} d x

d er i v a t i v e 24 x - 0.01 x^{2}

y^{^{''}} + 121 y = sec (11 x)