integral from-8 to 0 of 1/(\sqrt[3]{x)}

Lösung

\int_{- 8}^{0} \frac{1}{3 x} d x

- 6 (- 1)^{\frac{2}{3}}

Schritte zur Lösung

\int_{- 8}^{0} \frac{1}{3 x} d x

Wende die Potenzregel an

= [\frac{3}{2} x^{\frac{2}{3}}]_{- 8}^{0}

Berechne die Grenzen:

- 6 (- 1)^{\frac{2}{3}}

= - 6 (- 1)^{\frac{2}{3}}

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