integral from 3 to-1 of t^2

Lösung

\int_{3}^{- 1} t^{2} d t

- \frac{28}{3}

Dezimale

- 9.33333 \dots

Schritte zur Lösung

\int_{3}^{- 1} t^{2} d t

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{- 1}^{3} t^{2} d t

Wende die Potenzregel an

= - [\frac{t ^{3}}{3}]_{- 1}^{3}

Berechne die Grenzen:

\frac{28}{3}

= - \frac{28}{3}

\int_{0}^{1} \frac{18}{x ^{2} - 9} d x

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\int_{0}^{36} \frac{9}{36 - x} d x