xy^'=xy

Lösung

x y^{^{'}} = x y

y = e^{x + c_{1}}

Schritte zur Lösung

x y^{'} (x) = x y

Solve separable ODE:

y = e^{x + c_{1}}

y = e^{x + c_{1}}

x^{^{'}} = 1 + x

f (x) = (x - 1) 2 (x + 1) f^{^{'}} (x)

\frac{d y}{d x} = \frac{( 3 x ^{2} )}{e ^{y} + 1}

y^{^{'}} = x y - 8 x

x^{^{'}} = - (1 - x) (2 - x)