y^'=(12ln^3(x))/(xe^y)

Lösung

y^{^{'}} = \frac{12 ln ^{3} ( x )}{x e ^{y}}

y = ln (3 ln^{4} (x) + c_{1})

Schritte zur Lösung

y^{'} (x) = \frac{12 ln ^{3} ( x )}{x e ^{y}}

Solve separable ODE:

y = ln (3 ln^{4} (x) + c_{1})

y = ln (3 ln^{4} (x) + c_{1})

y^{2} + y = (x^{2} - x) y^{^{'}}

x y^{^{'}} - y = 3

(5 + y) y^{^{'}} = sin (7 + x)

y^{^{'}} + 6 e^{x + y} = 0

(1 - cos (x)) d y + (2 y sin (x) tan (x)) d x = 0